about #FORALL
 

Here I want to ask a question with a loop command.

When I make auto-quests robot, I have set a trigger to catch what quests can be bought in hockshop.
such as:
"$N对$n说道：正好正好，妾身占签得知$w现急需$o。\
"$N对$n点头说道：相公刚说了，让妾身征集什么",
"$N想了一下，对$n说道：老夫听说军务处想要 blah blah
I catched 3 variables : Q_give,Q_armor,Q_weapon
and judged them as buyable with my DB.
Then I use #ADDITEM to creat a variable @Q_buy={@Q_give|@Q_armor|@Q_weapon}
such as {大板斧|金环锁子甲|青锋剑}

Then I go to the hockshop to buy them.
#FORALL @Q_buy {buy %i}
#TRIGGER {你从当铺买到了一*} {#DELITEM @Q_buy %1}

However, you know, buy something from hockshop make a little busy, that I can not buy 3 things in one time.
How can I insert the #wa 2000 into the loop? or use other command, then what?
Waiting for your kindly suggestion.Thank you all.

饭要一口一口的吃，任务要一个一个的做。
 

young..

为什么搞得这么复杂呢？多用几个trigger不好吗？既简单，考虑的因素又少，还很容易debug。
nod fengyue

#var Q 大板斧|金环锁子甲|青锋剑
#var step
#var Qnum
Qnum=%numitems(@Q)
#if (@Qnum=0) {TODO} {step=1}
buy %item(@Q,@step)

#TRIGGER {你从当铺买到了一*} {#wa 2000
#ad step 1
#if (@step>@Qnum) {TODO} {buy %item(@Q,@step)}}

方法就是这样，不过就像sandman和fy说的一样要在quest robot中实现是不可能的

QUEUE啊..........
看到就^痛

You all are so warmheart!
Thanks you all!

Thanks fengyue's suggestion, however I have made a trigger seem with Nirvana's idea like this:

#if (@Qnum=0) {TODO} {step=1}
buy %item(@Q,@step)
#TRIGGER {你从当铺买到了一*} {#wa 2000
#ad step 1
#until (@step>@Qnum) {buy %item(@Q,@step)}}

And here I want to ask another questions

If the gold or silver is not enough when auto-quest
How can I go back to withdraw gold
and continue doing my task (How can I judge I'm doing weapon|armor|food...blah blah)?
I have a idea with %trigger(), but it seems too many elements to consider
Thanks!

..............
 

goback withdraw->reset->buy @item from dp
身上多带点钱不就是了。。至于嘛。。

回复: about #forall
 

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